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xxTIMURxx [149]
3 years ago
5

What is the domain of

qrt{8-8x} " align="absmiddle" class="latex-formula">
please use interval notation. Thanks.
Mathematics
2 answers:
RoseWind [281]3 years ago
6 0
8-8x\geq0\\
8x\leq8\\
x\leq1\\
x\in(-\infty,1]
Fed [463]3 years ago
3 0
To find the domain of a function with a root, you set it ≥ 0
So, the equation will look like this:
8 - 8x ≥ 0
-8x ≥ 8
-8x ÷ 8 ≤ 8 ÷ -8
x ≤ 1
Therefore, the domain is
(-∞, 1]
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We need to get y on one side.
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We need to get 2y by itself.
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Divide both sides by -2 to solve for y.
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I hope this helps!
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Natasha_Volkova [10]

Option A. 5/8 is the correct answer.

Step-by-step explanation:

Square root by factorization will be used to solve this question.

Given

\sqrt{\frac{25}{64}}

The square root can be applied to numerator and denominator separately

=\frac{\sqrt{25}}{\sqrt{64}}

Factorization

=\frac{\sqrt{5*5}}{\sqrt{2*2*2*2*2*2}}\\=\frac{\sqrt{5^2}}{\sqrt{2^2*2^2*2^2}}\\=\frac{5}{2*2*2}\\=\frac{5}{8}

Hence,

Option A. 5/8 is the correct answer.

Keywords: Square roots, factorization

Learn more about square root at:

  • brainly.com/question/10364988
  • brainly.com/question/10435816

#LearnwithBrainly

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