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3 years ago

Simplify the equation _3(_7x_5)

Mathematics

1 answer:

jek_recluse [69]3 years ago

5 0

21X_15 :-) :-) :-)!!!!! There you go!

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Seventeen consecutive positive integers have a sum of 306. What is the sum of the seventeen consecutive integers that immediatel

Stels [109]

Answer:

595

Step-by-step explanation:

Each of the following 17 is 17 more than its corresponding integer in the 1st 17.

---> 306 + 289 = 595

8 0

3 years ago

The product of two numbers is 30. If one of the numbers is 15/, what is the other number?

PSYCHO15rus [73]

Answer:

The other number is 2 if the given number is 15.

Step-by-step explanation:

One of the numbers is 15, correct?

Let the other number be x.

15 × x = 30

x = 30/15

x = 2.

Let's check:

15 × 2 = 30.

30 = 30.

Correct!

3 0

3 years ago

Read 2 more answers

If you are given the length of a hypotenuse and the length of an adjacent side, what

Evgen [1.6K]

Answer:

cosine

Step-by-step explanation:

6 0

3 years ago

Suppose that 7 in every 10 auto accidents involve a single vehicle. If 15 auto accidents are randomly selected, compute the prob

kobusy [5.1K]

Answer:

$\mathbf{P(X \le 4 ) \simeq 0.0006722}$

Step-by-step explanation:

From the information given:

p = x/n

p = 7/10

p = 0.7

sample size n = 15

Suppose X be the number of accidents involved by a single-vehicle.

Then;

$X \sim Binom (15,0.7)$

Thus, the required probability that at most 4 involve in a single-vehicle is

$P(X\le 4) \\ \\P(X \le 4) = P(X = 0) + P(X =1 ) + ... + P(X = 4)$

$P(X \le 4 ) = (^{15}_0) *0.7^0 *0.3^{15-0} + (^{15}_1) *0.7^1 *0.3^{15-1} + (^{15}_2) *0.7^2 *0.3^{15-2} + (^{15}_3) *0.7^3 *0.3^{15-3} + (^{15}_4) *0.7^4 *0.3^{15-4}$

$P(X \le 4 ) = (\dfrac{15!}{0!(15-0)!}) *0.7^0 *0.3^{15-0} + (\dfrac{15!}{1!(15-1)!}) *0.7^1 *0.3^{15-1} + (\dfrac{15!}{2!(15-2)!}) *0.7^2 *0.3^{15-2} + (\dfrac{15!}{3!(15-3)!}) *0.7^3 *0.3^{15-3} + (\dfrac{15!}{4!(15-4)!}) *0.7^4 *0.3^{15-4}$

$P(X \le 4 ) =1.4348907 \times 10^{-8} +5.02211745 \times 10^{-7} + 8.20279183 \times 10^{-6} + 8.29393397 \times 10^{-5} + 5.80575378 \times 10^{-4}$

$P(X \le 4 ) =6.7223407 \times 10^{-4}$

$\mathbf{P(X \le 4 ) \simeq 0.0006722}$

3 0

3 years ago

Write and solve a problem for 42÷7 in which the quotient is the number of groups

Nat2105 [25]

Answer:

Step-by-step explanation:

7 0

4 years ago