2a + 4 - 7a + a
2a -7a +a +4
-5a + a +4
-4a + 4
-4a + 4 is your answer
hope this helps
Answer:
Theanswer is 4/27.
Step-by-step explanation:
given that, F(x) = 4×(1/3)^x
now , F(3)= 4×(1/3)^3 ( putting value of x)
or, F(3) = 4×(1/27)
therefore, F(3)= 4/27... ans
<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>
The mass of radioactive material remaining after 50 years would be 48.79 kilograms
<h3>How to determine the amount</h3>
It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.
Given the radioactive decay formula as
m(t)=120e−0.018t
Where
t= 50 years
m(t) is the remaining amount
Substitute the value of t
![m(t) = 120e^-^0^.^0^1^8^(^5^0^)](https://tex.z-dn.net/?f=m%28t%29%20%3D%20120e%5E-%5E0%5E.%5E0%5E1%5E8%5E%28%5E5%5E0%5E%29)
![m(t) = 120e^-^0^.^9](https://tex.z-dn.net/?f=m%28t%29%20%3D%20120e%5E-%5E0%5E.%5E9)
Find the exponential value
m(t) = 48.788399
m(t) = 48.79 kilograms to 2 decimal places
Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms
Learn more about half-life here:
brainly.com/question/26148784
#SPJ1
The Answer Is B
Use proportions to find x% of the children playing on the swings.
![\frac{21}{100} = \frac{5}{x\%}](https://tex.z-dn.net/?f=%20%5Cfrac%7B21%7D%7B100%7D%20%20%3D%20%20%5Cfrac%7B5%7D%7Bx%5C%25%7D%20)
![x = 23.80952380\%](https://tex.z-dn.net/?f=x%20%20%3D%2023.80952380%5C%25)
Meaning B is correct.
Answer:
i) Point B is located at 0.
ii) The two points that are opposite are 5 / 5 and 10 / -5 and 5 / 5, 10 and -5, -10.
iii) Point D is located at 35.
iv) -20 is one tick mark to the left of point A.