The diagram represents a difference of squares.

2 answers:

7 0

The answer is d.

Explanation:
To start with, classify the first two terms and factor out the common factor. i.e m is a common factor of m2-6m. By factoring it out we get m(m-6).

Follow the same procedure for terms three and four. ie
6 is a common factor of 6m-36. By factoring out, 6(m-6)
Regrouping
m(m-6)+6(m-6)
By factoring out (m-6), we get:
(m-6)(m+6)

stealth61 [152]3 years ago

7 0

Answer:

Option D $(m-6)(m+6)$

Step-by-step explanation:

we have

$m^{2} -6m+6m-36$

Simplify

$m^{2} -6m+6m-36=m^{2} -36$

we know that

In a difference of square

$(a^{2}-b^{2})=(a+b)(a-b)$

Remember that

$36=6^{2}$

therefore

$(m^{2}-6^{2})=(m+6)(m-6)$

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okay so the problem is "A circle is centered at the point (-3,2) and passes through the point (1,5). The radius of the circle is

Nesterboy [21]

Answer:

A circle is centered at the point (-3,2) and passes through the point (1,5). The radius of the circle is (5 ) units. the point (-7, -1) and point (-7, 5) lies in this circle.

Step-by-step explanation:

equation of circle is

(X-center_X)^2 + (y-center_Y)^2 = r^2

==> (x+3)^2 + (y-2)^2 = r^2

Now it passes 1,5 so

4^2+3^2 = 5^2

==> r = 5

when x = -7

y = -1 or 5

5 0

3 years ago

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