Everything changed when the fire nation attacked

Mathematics

1 answer:

sergejj [24]3 years ago

7 0

Answer:

What is the question?

Step-by-step explanation:

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A total of 132 potential customers visit 22 vendors at a flea market. What is the ratio of customers to vendors?

babunello [35]

The ratio would be 132:22
since, it is customers to vendors.
The key word is "to" which indicates the order of the ratio.
Hope this helped.

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3 years ago

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Which equation is true for x = 1.8? x3 = 0.6 3x = 7.2 x + 3.1 = 5.5 6 = 3.6 + x

Olin [163]

Answer B

Step-by-step explanation:

Your answer should be written in paragraph/essay format.

Any sources used should be cited at the bottom of your paper.

All answers should show you have learned something from Unit 9. Material from other units will not be graded for this assignment.

If you are stuck, you can think about the following topics: textile mills, interchangeable parts, the Lowell System, unions, labor reform, steamboats, railroads, coal, the telegraph, and/or new inventions.

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3 years ago

g how many square feet of roofing is needed for the roof of a building that is 32 ft wide and 62 ft long? the slope of the roof

Ludmilka [50]

The area of the roof is 1984 sq. ft. 1984 square feet of roofing is needed for the roof of a building that is 32 ft wide and 62 ft long.

Given, the length of the roof is 62 ft long and the width of the roof is 32 ft wide. Therefore, the area of the roof is length * width.

Area of the roof = length of the roof * width of the roof

Area = 62 ft * 32 ft

Area = 1984 sq. ft

Here, also given the slope of the roof is 1:2 which indicates the ratio of rise and run.

Slope of the roof = Rise / Run = 1 / 2

Then, the slope factor is $\frac{\sqrt{\frac{ 1^{2} }{2 ^{2} } }}{12}$ = $\frac{1}{24}$ = 0.04167

To see a similar example:

brainly.com/question/27301581

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The right question is:

How many square feet of roofing is needed for the roof of a building that is 32 ft wide and 62 ft long?

4 0

1 year ago

The value of log3 5 x log25 9 is

Rama09 [41]

$\log_{3}5\cdot\log_{25}9=\dfrac{1}{\log_{5}3}\cdot\log_{25}9=\dfrac{1}{\log_{5}3}\cdot\log_{5^2}9=\dfrac{1}{\log_{5}3}\cdot\dfrac{1}{2}\log_{5}9=\\\\\\=
\dfrac{1}{\log_{5}3}\cdot\dfrac{1}{2}\log_{5}3^2=\dfrac{1}{\log_{5}3}\cdot\dfrac{2}{2}\log_{5}3=\dfrac{1}{\log_{5}3}\cdot\log_{5}3=\dfrac{\log_{5}3}{\log_{5}3}=\boxed{1}$