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ivolga24 [154]
3 years ago
8

If Sarah rents a washer and dryer for $52 per month for 13 months how much will she pay for 13 months?

Mathematics
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

She would pay $676

Step-by-step explanation:

Vikki [24]3 years ago
3 0

Answer:

$676

Step-by-step explanation:

52x13= 676

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Jawan made a table to figure out how much he earns at his job (image below)
slega [8]

Answer:

Th rule here is that every week he works 6 more hours and in those six hours he adds $54 to the original price

Step-by-step explanation:

Answer for question B:

324

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Pls answer this i need help
Vitek1552 [10]

Step-by-step explanation:

your don't see what went wrong ?

Tyrell worked on

16 - 2(4 + 3x)

what do brackets mean ? they mean that this operation has to be done before everything else in the expression.

as this contains a variable, we cannot fully calculate it, true, but we need to keep this in mind and always treat the content of the brackets as one package.

so, whatever I do from the outside with one part of that package, I have to do also with all the other parts of that package.

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Amelia multiplied correctly, but then made a mistake summing things up

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6 0
3 years ago
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

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3 years ago
Two expressions that are equivalent to 5.75 ÷ 1.15.
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Answer:

i think the answe is A and B hope this helps

Step-by-step explanation:

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yes Wyatt is very correct

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