According to Question , both the graph have same shape . If we look at the the first graph it cuts x - axis at (0 , 2) and ( 0 , -2) . Hence x = 2 and -2 are the zeroes of the equation .

And ,the given function is ,

$\implies f(x) = 4 - x^2 \\\\\implies f(x) = 4-x^2=0 \\\\\implies 2^2-x^2=0\\\\\implies (2-x)(2+x) = 0 \\\\\boxed{\red{\bf \implies x = 2 , (-2) }}$

Hence ,we can can see that x = 2 and (-2) are the zeroes of graph. 

This implies that if we know the zeroes , we can frame the Equation.

On looking at second parabola , it's clear that cuts x - axis at ( 1, 0 ) and (-1,0). So , 1 and -1 are the zeroes of the quadratic equation . Let the function be g(x) . Here , a and ß are the zeroes.

$\implies g(x) = (x-\alpha)(x-\beta) \\\\\implies g(x) = (1+x)(1-x) \\\\\boxed{\pink{\bf \implies g(x) = 1 - x^2}}$

Hence option B is correct .

8 0

3 years ago

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Solve the following inequality: x+5≤(−x+2)+x

vesna_86 [32]

Answer:

Step-by-step explanation:

x + 5 ≤ ( - x + 2) + x

Remove the parenthesis

That's

x + 5 ≤ - x + 2 + x

x + 5 ≤ 2

Using the subtraction property subtract 5 from both sides

That's

x + 5 - 5 ≤ 2 - 5

x ≤ 2 - 5

We have the final answer as

Hope this helps you

4 0

3 years ago