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Valentin [98]
3 years ago
9

What do you think is the best way to measure the distance from point to line

Mathematics
2 answers:
Nonamiya [84]3 years ago
4 0
You would probably have to measure it greatest distance by ur least distance and subtract or add
aniked [119]3 years ago
3 0
Subtract distances, or in some cases Pythagorean Theorem might be needed if the points create a diagonal
You might be interested in
The height of a parallelogram is one-third its base. If the area of the parallelogram is 363 square inches, find its base and he
kipiarov [429]

Answer:

Height = 11 inches

Base = 33 inches

Step-by-step explanation:

In this question, we are asked to find the height and base of a parallelogram given the area of the parallelogram.

From the question, we are told that height is 1/3 of base. This means that base is 3 times the height

So if we represent the height with variable h, then the base is 3h

Mathematically the area of a parallelogram can be calculated by the formula

A = bh

Thus ,

363 = h * 3h

3h^2 = 363

divide through by 3

h^2 = 121

h = √121

h = 11 inches

since b = 3h , then b = 3 * 11 = 33 inches

8 0
3 years ago
PLEASE HELP
MAXImum [283]

The answer is x=34 degrees.

6 0
2 years ago
Read 2 more answers
Kindly solve this question 6 too !!
Shkiper50 [21]

Answer:

x=1

Step-by-step explanation:

~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1

7 0
2 years ago
PLZ HELP...Enter in standard form the equation of the line passing through the given point and having the given slope.
Alenkinab [10]

Standard form for the equation of the line is

$y=-\frac{2}{3} x-\frac{25}{3}

Solution:

Given point is (2, –5).

slope of the line m = -\frac{2}{3}

Here, x_1=2, y_1=-5

Equation of a line passing through the point:

y-y_1=m(x-x_1)

$y-(-5)=-\frac{2}{3} (x-(-5))

$y+5=-\frac{2}{3} (x+5)

$y+5=-\frac{2}{3} x-\frac{10}{3}

Subtract 15 from both sides of the equation.

$y+5-5=-\frac{2}{3} x-\frac{10}{3}-5

$y=-\frac{2}{3} x-\frac{25}{3}

Standard form for the equation of the line is

$y=-\frac{2}{3} x-\frac{25}{3}

7 0
3 years ago
If the 32 ounce bottle is 20% more than the typical bottle, how many ounces are in the typical bottle? Round your answer to the
Elenna [48]
6.4 %. hope that helped
4 0
3 years ago
Read 2 more answers
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