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Setler79 [48]
3 years ago
12

Which point approximates the solution to the

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0

Answer: (1.25,0.25)

Step-by-step explanation:

Because I got it right.

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Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
WITCHER [35]

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0
1 year ago
2m= cm <br><br><br> Pls help me!!!
Andrej [43]

Answer:

200cm

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
what is the volume of a cylinder, in cubic inches, with a height of 2 inches and a base diameter of 4 inches? Round to the neare
seraphim [82]

Answer:

V≈25.13in³

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Phil has to put the greatest number of apples and oranges in each of box so each box have the same number of apples and oranges
Andrews [41]
Least common multiple
4 0
2 years ago
F(x)=x2 what is g(x)?
Oksi-84 [34.3K]

g(x) = (1/4)x^2 . correct option C) .

<u>Step-by-step explanation:</u>

Here we have , f(x)=x^2  and we need to find g(x) from the graph . Let's find out:

We have ,  f(x)=x^2   . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !

A . g(x) = (1/4x)^2

Putting (2,1) in equation g(x) = (x/4)^2 , we get :

⇒ g(2)= (\frac{2}{4} )^2

⇒ 1\neq \frac{1}{4}

Hence , wrong equation !

B . g(x) = 4x^2

Putting (2,1) in equation g(x) = 4x^2 , we get :

⇒ g(2)=4(2)^2

⇒ 1\neq 64

Hence , wrong equation !

C . g(x) = (1/4)x^2

Putting (2,1) in equation g(x) = (1/4)x^2 , we get :

⇒ g(2)= (\frac{1}{4} )2^2

⇒ 1= 1

Hence , right equation !

D . g(x) = (1/2)x^2

Putting (2,1) in equation g(x) = (1/2)x^2 , we get :

⇒ g(2)= (\frac{1}{2} )2^2

⇒ 1\neq 2

Hence , wrong equation !

Therefore , g(x) = (1/4)x^2 . correct option C) .

8 0
3 years ago
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