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sergejj [24]
3 years ago
10

Two consecutive, odd integers have the property that when the smaller is add to twice the larger, the sum is 43. Find an equatio

n that could be used to determine the smaller integer represents by the variable n.
​
Mathematics
1 answer:
loris [4]3 years ago
6 0
If the smaller integer is n, then the larger one has to be n+2

n + 2(n+2) = 43
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Which solution of the equation can be determined from the graph? The solution is? The set of the other solution is?
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SOLUTION

The given equation is

x^3+3x^2-16x-48=0

From the given graph, one of the solution of the equation is

x=4

Since x=4 is a solution to the equation it follows that x-4 is a factor

The given equatin can be simplified as

x^3+3x^2-16x-48=(x-4)(x+4)(x+3)

Therefefore other solutions are

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1 year ago
Marya wants to factor the polynomial 36x3 – 22x2 – 144x. Which term can she add to the polynomial that would not change its grea
Dafna11 [192]

Answer:

-50xy and -40x²

Step-by-step explanation:

1) Common factor of the letters: x, x², and x³.

It is the common letter with the lowest exponent: x

2) Common factors of the coefficients (numbers): 36, 22, and 144

i) prime factors of 36: 36 = 2² × 3²

ii) prime factors of 22: 22 = 2 × 11

iii) prime factors of 144: 2⁴ × 3²

iv) Greatest common factor: the repeated number raised to the lowest power: 2.

3) Therefore, the greatest common factor of the terms 36x³ - 22x² - 144x is 2x

4) Any number that has 2x as a factor will not change this common factor.

5) Factors of the choices:

i) –11: 2x is not a factor of - 11, therefore this does not apply

ii) –50xy: 2x is a factor, since - 50xy / (2x) = - 25y, therefore this applies.

iii) –40x²: 2x is a factor, since - 40x² / (2x) = -20x, therefore this applies

iv) 24: 2x is not factor of 24, therefore this does not apply

v) 10y: 2x is not a factor of 10y, therefore this does not apply

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3 years ago
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Then the answer is the option D) s>0 and V(s) > 0.
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What is the distance between the points (2, 1) and(6, 7)?
icang [17]

Answer:

\displaystyle d = 2\sqrt{13}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

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<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

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Point (6, 7)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(6 - 2)^2 + (7 - 1)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{4^2 + 6^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{16 + 36}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{52}
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