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DENIUS [597]
1 year ago
9

Which solution of the equation can be determined from the graph? The solution is? The set of the other solution is?

Mathematics
1 answer:
Gennadij [26K]1 year ago
6 0

SOLUTION

The given equation is

x^3+3x^2-16x-48=0

From the given graph, one of the solution of the equation is

x=4

Since x=4 is a solution to the equation it follows that x-4 is a factor

The given equatin can be simplified as

x^3+3x^2-16x-48=(x-4)(x+4)(x+3)

Therefefore other solutions are

x=-4,x=-3

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What is the value of b:<br><br> 14.4= -2.4b
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Solve each calculation. Be sure to report your answer with the correct number of significant figures.
Serjik [45]

Question:

Solve each calculation. Be sure to report your answer with the correct number of significant figures.

5.61000 dg  × 1.1010 dg  

12.0 m  ÷ 3.1415 m

Answer:

1. 5.61000dg  * 1.1010dg = 6.177 dg^2

2. \frac{12}{3.1415} = 3.8198

Step-by-step explanation:

1. 5.61000 dg  × 1.1010 dg  

We start by representing each digit using scientific notation

5.61000 = 561000 * 10^{-5}

1.1010 = 11010 * 10^{-4}

Then, Multiply both numbers

561000 * 10^{-5} * 11010 * 10^{-4}

First, rearrange

561000  * 11010 * 10^{-5} *  10^{-4}

6176610000 * 10^{-5} *  10^{-4}

From law of indices, 10^{-5} *  10^{-4} = 10^{-9};

So, we have

6176610000 * 10^{-9}

6.176610000

Because 5.61000 is given in 3 significant figures and 1.1010 is given in 4 significant figures, we approximate the result to 4 significant figures

This gives 6.177

Hence, 5.61000dg  * 1.1010dg = 6.177 dg^2

2.

12.0 m  ÷ 3.1415 m

Using proper notation

12.0 m ÷ 3.1415 m = \frac{12}{3.1415}

We start by representing 3.1415 using scientific notation

3.1415 = 31415 * 10^{-4}

By substitution;

\frac{12}{3.1415} = \frac{12}{31415 * 10^-4}

Take 10^{-4} to the numerator

\frac{12}{3.1415} = \frac{12 * 10^4}{31415}

From law of indices, 10^{4} = 10000

\frac{12}{3.1415} = \frac{12 * 10000}{31415}

Multiply

\frac{12}{3.1415} = \frac{120000}{31415}

Divide

\frac{12}{3.1415} = 3.81983129078

Because 12.0 is given in 2 significant figures and 3.1415 is given in 5 significant figures, we approximate the result to 5 significant figures

\frac{12}{3.1415} = 3.8198

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