Question

Which solution of the equation can be determined from the graph? The solution is? The set of the other solution is?

Answer 1

SOLUTION

The given equation is

$x^3+3x^2-16x-48=0$

From the given graph, one of the solution of the equation is

$x=4$

Since x=4 is a solution to the equation it follows that x-4 is a factor

The given equatin can be simplified as

$x^3+3x^2-16x-48=(x-4)(x+4)(x+3)$

Therefefore other solutions are

$x=-4,x=-3$