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hammer [34]
3 years ago
8

A photographer made a 5-inch by 8-inch print of a photo. He then made a 10-inch by 16-inch print of the same photo. Which scale

factor was use to create the larger photo from the smaller photo?
A. 2

B. 4

C. 5

D. 6

E. 8
Mathematics
1 answer:
torisob [31]3 years ago
7 0
A.2 because 8*2 =16 and 5*2=10
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Can someone please help me and explain
julia-pushkina [17]

Answer:  (x-2) inches.

The question asks for length in square inches.  There is no such thing.  It should read in inches.  Since it is a square frame, we can take the square root of (x^2-4x+4), which is (x-4).  This is in incnes

Step-by-step explanation:

(x-4)*(x-4) = x^2-4x+4

4 0
3 years ago
Jordan is saving to buy a computer that costs $425. So far she has saved $125, and she adds $20 to her savings each week. How ma
Ber [7]

Answer:

15 more weeks

Step-by-step explanation:

425 - 125 (what shes already saved)

300 divided by 20 (amount shes saving each week)

Result is 15, so 15 more weeks.

Hope this helped :)

If you mean how many weeks total, 125 according to the 20 dollars a week would bring it 22 weeks i think.. since the answer answer is 21.2 weeks exactly when you divide 425 by 20.

4 0
3 years ago
Frederick designed an experiment in which he spun a spinner 20 times and recorded the results of each spin.
belka [17]

Answer:

the statements given above are true.

Step-by-step explanation:

Given that Frederick designed an experiment in which he spun a spinner 20 times and recorded the results of each spin.  

He spun a 4 five times.

The statements true are:

i) For the experimental outcomes to be closer to the predicted outcome, the number of trials should be increased.

iii) If the number of trials is changed, the experimental probability also changes.

iv) If the number of trials is changed, the predicted number of outcomes also changes.

v) If the number of trials is changed, the number of experimental outcomes also changes.




5 0
3 years ago
Read 2 more answers
A/20 + 14/15 = 9/15 <br><br> Can i get some help?
KiRa [710]
Method 1:

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |multiply\ both\ sides\ by\ 60\\\\60\cdot\dfrac{a}{20}+60\cdot\dfrac{14}{15}=60\cdot\dfrac{9}{15}\\\\3a+4\cdot14=4\cdot9\\\\3a+56=36\ \ \ \ |subtract\ 56\ from\ both\ sides\\\\3a=-20\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=-\frac{20}{3}\to a=-6\frac{2}{3}}

Method 2.

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |subtract\ \dfrac{14}{15}\ form\ both\ sides\\\\\dfrac{a}{20}=-\dfrac{5}{15}\\\\\dfrac{a}{20}=-\dfrac{1}{3}\ \ \ \ |multiply\ both\ sides\ by\ 20\\\\\boxed{a=-\dfrac{20}{3}\to a=-6\frac{2}{3}}
3 0
3 years ago
For what values of a does the equation a+x= 1+xa^2 have no solution?
Anton [14]

Answer:

We have the equation

a+x= 1+xa^2

we leave the terms with x on the left side of the equation and the independent terms on the right side.

x-xa^2=1-a\\(1-a^2)x=1-a\\

resolving for x we have that

x=\frac{1-a}{1-a^2}

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when 1-a^2=0\\1=a^2\\a=\pm1

Then, for a=\pm1 the equation hasn't solution

7 0
3 years ago
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