Answer:
Step-by-step explanation:
The question reads much more complicatedly than the actual equation.
Sakura * x = Nanuto
412 x = 634 Divide by 412
x = 634/412
x = 1.54 times
The closest answer is 3/2 as far. 1.54 is just about 3/2.
So base on your question the possible answer to that kind of question and the solution are the following and i hope you will understand the formula and free to ask some questions if needed.
<span>2<span>cos2</span><span>x2</span>=1+cosx=1−<span>1517</span>=<span>217</span>,<span>cos2</span><span>x2</span>=<span>117</span></span>
<span>cos<span>x2</span>=−<span>1<span>17<span>−−</span>√</span></span>....(1)</span>
<span>sin<span>x2</span>=<span>1<span>17<span>−−</span>√</span></span>,90<<span>x2</span><135</span>
<span>sin<span>x2</span>>0,cos<span>x2</span><0,tan<span>x2</span><0</span>
<span>2<span>sin2</span><span>x2</span>=1−cosx=1−<span><span>−15</span>17</span>=<span>3217</span>,sin<span>x2</span>=<span>4<span>17<span>−−</span>√</span></span>.....(2)</span><span>
divide (2) by (1) and get the value of tan x/2</span>
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Right triangles must follow the pythagorean theorem, so a^2+b^2=c^2.
Let's find a^2 and b^2 by squaring the first 2 side lengths.
(x^2-1)^2= x^4-2x^2+1
(2x)^2= 4x^2
Then add the two to find c^2
x^4+ 2x^2 +1= c^2
Root both sides
x^2+1=c
Since the side lengths can be plugged into the pythagorean theorem, the side lengths must represent a right triangle.
Hope this helps!
