Y^2+4y=-8
add 8 both sides
y^2+4y+8=0 in the form of ax²+bx+c=0
Factor it
by formula
-b+-(√b²-4ac)/2a
-4+-(√16-32)/2*1
-4+-(√-16)/2
-4+-4i/2
-2+-2i where√-1=i
Answer:
See answer below
Step-by-step explanation:
The possible zeroes are p/q where p is factors of the constant and q is factors of the coefficient of the largest degree.
This means possible zeroes are ±15/4, ±5/4, ±3/4, ±1/4, ±15/2, ±5/2, ±3/2, ±1/2, ±15, ±5, ±3, ±1.
Answer:
5.441683e+23
Step-by-step explanation:
Hope it helped brainiest plz
Answer:
The answer is "Analysis the information by chart and number processes".
Step-by-step explanation:
They already have articulated a query and also gathered information unless you are searching only at the distribution of your results. Those who are ready to analyze your results for all are there.

Subtract 4 from both sides.

Subtract 4 from 36 to get 32.

Divide both sides by −8. Since −8 is <0, the inequality direction is changed.

Divide 32 by −8 to get −4.

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