Answer:
1.8
Step-by-step explanation:
Answer:
Step-by-step explanation:
Take a triangle ABC, in which AB=AC.
Construct AP bisector of angle A meeting BC at P.
In ∆ABP and ∆ACP
AP=AP[common]
AB=AC[given]
angle BAP=angle CAP[by construction]
Therefore, ∆ABP congurent ∆ACP[S.A.S]
This implies, angle ABP=angleACP[C.P.C.T]
Considering the perimeter of a square, it is found that:
- The length of one side of the garage originally was of 61.5 ft.
- The length of one side of the garage now is of 92.25 ft.
- The percent increase in the length of one side was of 50%.
<h3>What is the perimeter of a square?</h3>
The perimeter of a square of side length s is given by four times the length, that is:
P = 4s.
Before the change, the perimeter was of 246 ft, hence:
4s = 246
s = 246/4
s = 61.5.
The length of one side of the garage originally was of 61.5 ft.
After that, the perimeter increased by 50%, hence:
P = 246 x 1.5 = 369.
4s = 369
s = 369/4
s = 92.25.
The length of one side of the garage now is of 92.25 ft.
The percent increase is the increase divided by the initial value, hence:
(92.25 - 61.5)/61.5 = 50%.
The percent increase in the length of one side was of 50%.
More can be learned about the perimeter of a square at brainly.com/question/10489198
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Complementary I’m sure but I could be wrong
