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vichka [17]
3 years ago
13

X2 =5. What is the answer for X

Mathematics
2 answers:
grin007 [14]3 years ago
7 0

Answer:

x=2.5

Step-by-step explanation:

First, you do 5 divided by 2, because you are trying to find a missing factor. After that, your answer, which is 2.5, is what x equals.

Hope that helps!

Nezavi [6.7K]3 years ago
3 0

Answer:

x=5/2 or x=-\sqrt{5} and \sqrt{5} look below for steps

Step-by-step explanation:

x*2=5

2x=5

x=5/2

------------------

x^2=5

x=-\sqrt{5} and \sqrt{5}

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3 years ago
Use the compound interest formula to determine the final value of the following amount. $1900 at 10.4% compounded monthly for 4.
nikklg [1K]

Answer:

$3027.80

Explanation:

The compound interest formula is the following.

A=P(1+\frac{r}{n})^{nt}

where

A = final amount

P = principle amount

r = interest rate / 100

n = number of compounds per interval

t = time interval

Now in our case,

A = unknown

P = $1900

r = 10.4/100

n = 12 months / year ( because the interest is compounded monthly)

t = 4.5 yrs

Therefore, the compound interest formula gives

A=1900(1+\frac{10.4/100}{12})^{12*4.5}

Using a calculator, we evaluate the above to get

\boxed{A=\$3027.80}

which is our answer!

8 0
1 year ago
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6 0
3 years ago
Read 2 more answers
Angel jogged around the park in 1 1/4 hr chris jogged same distance in 5/6 hrs how much longer did angel take then chris in hr??
QveST [7]
You will have to get the difference and get a common denominator but first combine the mixed number:
1 \:  \frac{1}{4}  -   \frac{5}{6}   =  \frac{5}{4}   -   \frac{5}{6} =  \frac{15}{12}   -   \frac{10}{12}
Then subtract the numbers
\frac{15}{12}  -  \frac{10}{12}  =  \frac{5}{12}
Angel took 5/12 hours longer than Chris
6 0
4 years ago
A Confidence interval is desired for the true average stray-load loss mu (watts) for a certain type of induction motor when the
Vaselesa [24]

Answer:

A sample size of 35 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the width W as such

W = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large must the sample size be if the width of the 95% interval for mu is to be 1.0:

We need to find n for which W = 1.

We have that \sigma^{2} = 9, then \sigma = \sqrt{\sigma^{2}} = \sqrt{9} = 3. So

W = z*\frac{\sigma}{\sqrt{n}}

1 = 1.96*\frac{3}{\sqrt{n}}

\sqrt{n} = 1.96*3

(\sqrt{n})^2 = (1.96*3)^{2}

n = 34.57

Rounding up

A sample size of 35 is needed.

3 0
3 years ago
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