All categories

4 years ago

What is the value of x in the figure ( 3x +8) 35

Mathematics

1 answer:

DENIUS [597]4 years ago

6 0

(3x + 8)35
(3x × 35) + (8 × 35)
105x = 280
x = 280/105 = x = 56/21

You might be interested in

6) 98=4b+ 2c; Find b if c=5

andreev551 [17]

The answer is b= 22 :)

8 0

3 years ago

Helppppppppp please

mariarad [96]

Well here's the equation 4x3 x2=24 for both of the sides and the top 10x2 because if 4 is the bottom and the sides are 6 6-4=2 so 10x2=20 and we add the areas and

20

+

24

_____

44 is the combined areas (Your answer 44)

HOPE THIS HELPS :D

4 0

3 years ago

Read 2 more answers

What equation represents the linear equation shown in the graph? Enter your answer in the box. Write your answer in the form y =

leonid [27]

It would be y = -1/4x + 4

5 0

3 years ago

Read 2 more answers

[ INDICES]- Simplify :

just olya [345]

Answer is in the attachment.

note:

make a slight change in question 1;

7 0

3 years ago

Read 2 more answers

\int (x+1)\sqrt(2x-1)dx

Nezavi [6.7K]

Answer:

$\int (x+ 1) \sqrt{2x-1} dx = \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15}(2x-1)^{\frac{5}{2}} + C$

Step-by-step explanation:

$\int (x+1)\sqrt {(2x-1)} dx\\Integrate \ using \ integration \ by\ parts \\\\u = x + 1, v'= \sqrt{2x - 1}\\\\v'= \sqrt{2x - 1}\\\\integrate \ both \ sides \\\\\int v'= \int \sqrt{2x- 1}dx\\\\v = \int ( 2x - 1)^{\frac{1}{2} } \ dx\\\\v = \frac{(2x - 1)^{\frac{1}{2} + 1}}{\frac{1}{2} + 1}} \times \frac{1}{2}\\\\v= \frac{(2x - 1)^{\frac{3}{2}}}{\frac{3}{2}} \times \frac{1}{2}\\\\v = \frac{2 \times (2x - 1)^{\frac{3}{2}}}{3} \times \frac{1}{2}\\\\v = \frac{(2x - 1)^{\frac{3}{2}}}{3}$

$\int (x+1)\sqrt(2x-1)dx\\\\ = uv - \int v du$

$= (x +1 ) \cdot \frac{(2x - 1)^{\frac{3}{2}}}{3} - \int \frac{(2x - 1)^{\frac{3}{2}}}{3} dx \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ u = x + 1 => du = dx \ ]$

$= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \int (2x - 1)^{\frac{3}{2}}} dx\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \times ( \frac{(2x-1)^{\frac{3}{2} + 1}}{\frac{3}{2} + 1}) \times \frac{1}{2}\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \times ( \frac{(2x-1)^{\frac{5}{2}}}{\frac{5}{2} }) \times \frac{1}{2}\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15} \times (2x-1)^{\frac{5}{2}} + C\\\\$

6 0

3 years ago