8.
2 answers:
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Answer:
1)
2)
Where c represent the number of categories c=2
Step-by-step explanation:
Previous concepts
A chi-square goodness of fit test "determines if a sample data matches a population".
A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".
Assume the following dataset:
Tall =30 , Short =20
We need to conduct a chi square test in order to check the following hypothesis:
H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.
H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.
Part 1
So then we know that the expected values would be 25 for each case
The statistic to check the hypothesis is given by:
And if we replace we got:
Part 2
For this case the degreed of freedom are given by:
Where c represent the number of categories c=2
And we can calculate the p value given by:
And we can find the p value using the following excel code:
"=1-CHISQ.DIST(2,1,TRUE)"
<u>Answer: </u>
The car’s rate in kilometer per minute is 1.2 kilometer/minute and in 20 min it can travel 24 kilometer
<u>Solution: </u>
It is given that it can travel 72 kilometer per hour.
We know 1 hour = 60 min
So, the car travels in
60 min = 72 hour
Thus the cars rate in kilometer per minute is is 1.2 kilometer per minute.
Now we know in 1 minute the car can travel 1.2 kilometer.
Therefore in 20 minutes it will travel 1.2 20 kilometers= 24 kilometers