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3 years ago

7. What is the perimeter of a square with sidelengths of 4 inches?

Mathematics

1 answer:

irinina [24]3 years ago

7 0

Answer:

perimeter is 16 inches

Step-by-step explanation:

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Answer:

The 4th one is the least so you would put that as the first one, then the 2nd one, then the 1st one, then the 3rd one.

Step-by-step explanation:

The fourth one is first because 10 to the power of 0 is 0 times 10 to the power of 1 is still 0 minus 1 to the power of 10 is 1 so 0 minus 1 is -1. The second one is second because 10 to the power of 0 times 10 to the power of 1 is 0, times 1 to the power of 10 is still 0. The first one is third in line because 10 to the power of 0 plus 10 to the power of 1 is 10 times 1 to the power of 10 is 10. The third one is last because its the greatist, 10 to the power of 0 plus 10 to the power of 1 is 10 plus 1 to the power of 10 is 11.

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3 years ago

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$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

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3 years ago

7. What is the perimeter of a square with sidelengths of 4 inches?​

7. What is the perimeter of a square with sidelengths of 4 inches?