Answer:
d) the slope of f(x) is greater than the slope of g(x)
Step-by-step explanation:
to find the slope of an equation, you look at its rise/run. for f(x), you can see that from one point (0, 3) to another (1, 1) it goes down 2 values (3 - 1) and over 1 value (0 + 1). because it goes down 2 values, the rise is -2, and because it moves to the side 1 value positively, the run is +1.
-2/+1 = -2. this means the slope of f(x) = -2.
finally, it says the slope of g(x) = -6, and -2 > -6. i hope this helps! :)
The equation of any circle is
(x - a)^2 + (y - b)^2 = radius^2 where our center is (a, b)
Therefore, our equation is as follows.
(x + 2)^2 + (y - 3)^2 = 16
Answer:
The correct answer is D
Step-by-step explanation:
Hope this help
Answer:
-1_< x<6
Step-by-step explanation:
make sure to put when you put _< it's a less than with the little underline is under the less than
Recall what a parallel line is; two lines that are parallel are defined as having the same gradient or slope. Consider a line:
y = mx + b
If we want to find a certain line that is / parallel / to the original line passing through an arbitrary point (x₁, y₁), it is useful to understand the point-gradient or point-slope formula.
The gradient to the line y = mx + b is simply m. So, any parallel line to y = mx + b will have the same gradient. Examples include: y = mx + 1, y = mx + 200, y = mx + g
All we need to know, now, is to identify what specific line hits the desired point. Well, the point-gradient formula can help with that. Recall that the point-gradient formula is:
y - y₀ = m(x - x₀), where (x₀, y₀) is the point of interest.
Hence, it is useful to use the point-slope formula when asked for a point and a set of parallel lines to the original line.
