*see attachment for the missing figure
Answer:
Angle ADE = 45°
Angle DAE = 30°
Angle DEA = 105°
Step-by-step explanation:
Since lines AD and BC are parallel, therefore:
Given that angle Angle CBE = 45°,
Angle ADE = Angle CBE (alternate interior angles are congruent)
Angle ADE = 45° (Substitution)
Angle DAE = Angle ACB (Alternate Interior Angles are congruent)
Angle ACB = 180 - 150 (angles on a straight line theorem)
Angle ACB = 30°
Since angle DAE = angle ACB, therefore:
Angle DAE = 30°
Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)
Angle DEA = 180 - (45 + 30) (Substitution)
Angle DEA = 180 - 75
Angle DEA = 105°
Answer:
The coordinates of EF are E(5,-4) and F(1,-4).
The line segment EF is in QIV
Step-by-step explanation:
The line segment AB has vertices at: A(-4,5) and B(-4,1).
We apply the rule to reflect AB in the y-axis to obtain CD.
We apply the rule to rotate CD 90 degrees clockwise about the origin to obtain EF.
The coordinates of EF are E(5,-4) and F(1,-4).
See attachment
