Your answers will be A,B,D,
Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
Answer:
Step-by-step explanation:
A. k/5 = 3: Isolate k by multiplying both sides of this equation by 5:
k = 15
B. 3.5d = 70; Divide both sides by 3.5, obtaining d = 20
C. 4 1/2 = 1 1/2n; Rewrite 4 1/2 and 1 1/2 as improper fractions:
9/2 = (3/2)n. Now multiply both sides by (2/3): 3 = n
Ok, So What You Want To Do For The First One Is -4 Times What, Minus 2 Times What, Is 14. Your Going To Need To Explore With Numbers.
For The Second Problem Your Going To Need To Find Out -10 Times What, Plus 7 Times What, Is -25. Once Again, Your Going To Need To Explore With Numbers
Hope That Helped
