The solution for proving the identity is as follows:
sin(2A) = sin(A + A)
As sin(a + b) = sinacosb + sinbcosa,
<span>sin(A + A) = sinAcosA + sinAcosA
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<span>Therefore, sin(2A) = 2sinAcosA
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Answer:
y 0.4
x 0.3
Step-by-step explanation:
Answer:
<em>Cathy was born in 1980 and she was 18 years old in 1998</em>
Step-by-step explanation:
<u>Equations</u>
This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.
Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

In 1998, Cathy's age was

And it must be equal to the sum of the four digits

Rearranging

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

Operating

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]
c=8, d=0
Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18
Answer:
y = -3/2x + 6
Step-by-step explanation:
Parallel lines have the same slope so slope is -3/2
Using (4,0)
y = mx + b
0 = -3/2(4) + b
0 = -6 + b
b = 6
so y = -3/2x + 6
Answer:
22.05
Step-by-step explanation: