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Sonja [21]
3 years ago
10

Find the maximum or minimum value of the parabola. y = –2x^2 – 16x + 20

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

y=-20x+20

Step-by-step explanation:

Flura [38]3 years ago
5 0
This is the answer :
Y=-2^2- 16x+20
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Step-by-step explanation:

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stich3 [128]

Answer:

x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Step-by-step explanation:

Given;

x² - 2x - 1 = 0

Solve by completing the square method;

⇒ take the constant to the right hand side of the equation.

x² - 2x = 1

⇒ take half of coefficient of x = ¹/₂ x -2 = -1

⇒ square half of coefficient of x and add it to the both sides of the equation

x^2 +  (-1)^2 = 1 + (-1)^2

(x-1)^2 = 1 + 1\\\\(x-1)^2 = 2\\\\

⇒ take the square root of both sides;

x-1 = +/- \ \ \sqrt{2} \\\\x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Therefore, option B is the right solution.

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