Answer:
The answer is that w = 30
Step-by-step explanation:
To find this, we start by modeling the equation.
w/5 + 2 = 8
We know it looks like this since they say quotient, which means division problem.
w/5 + 2 = 8
w/5 = 6
w = 30
Not sure just need answers because I don’t no the answers
Answer:
-2 degrees Celsius.
Step-by-step explanation:
15 - 17 = -2
Answer:
45% probability that a randomly selected customer saw the advertisement on the internet or on television
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a customer saw the advertisement on the internet.
B is the probability that a customer saw the advertisement on television.
We have that:
![A = a + (A \cap B)](https://tex.z-dn.net/?f=A%20%3D%20a%20%2B%20%28A%20%5Ccap%20B%29)
In which a is the probability that a customer saw the advertisement on the internet but not on television and
is the probability that the customers saw the advertisement in both the internet and on television.
By the same logic, we have that:
![B = b + (A \cap B)](https://tex.z-dn.net/?f=B%20%3D%20b%20%2B%20%28A%20%5Ccap%20B%29)
12% saw it on both the internet and on television.
This means that ![A \cap B = 0.12](https://tex.z-dn.net/?f=A%20%5Ccap%20B%20%3D%200.12)
20% saw it on television
This means that ![B = 0.2](https://tex.z-dn.net/?f=B%20%3D%200.2)
37% of customers saw the advertisement on the internet
This means that ![A = 0.37](https://tex.z-dn.net/?f=A%20%3D%200.37)
What is the probability that a randomly selected customer saw the advertisement on the internet or on television
![A \cup B = A + B - (A \cap B) = 0.37 + 0.2 - 0.12 = 0.45](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%20A%20%2B%20B%20-%20%28A%20%5Ccap%20B%29%20%3D%200.37%20%2B%200.2%20-%200.12%20%3D%200.45)
45% probability that a randomly selected customer saw the advertisement on the internet or on television