Question

A survey asked students whether they have any siblings and pets. the survey data are shown in the relative frequency table.

Answer 1

Answer:

The likelihood that he or she has a pet given that a student does not have a sibling is:

Option: D ( 60%)

Step-by-step explanation:

Let A denote the event that a student does not have a sibling.

Let B denote the event that a students has a pet.

Then A∩B denotes the event that the student does not have a sibling but has a pet.

Let P denote the probability of an event.

Then, we are asked to find:

P(B|A)

We know that:

$P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}$

Also from the table we have:

P(A)=0.25

and P(A∩B)=0.15

Hence,

$P(B|A)=\dfrac{0.15}{0.25}\\\\P(B|A)=\dfrac{3}{5}\\\\P(B|A)=0.6$

which in percentage is:

$0.6\times 100=60\%$

Hence, the likelihood is:

60%