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trasher [3.6K]
3 years ago
15

Whats 5 divided by negative 3? its -15 right?

Mathematics
2 answers:
Umnica [9.8K]3 years ago
5 0

Answer: No

-1.666667 is the answer. When multiplying or dividing integers there are rules.

<u>Rules</u>

Multiplying or Dividing a Negative to a Negative the result will be a Positive.

Multiplying or Dividing a Negative to a Positive the result will be a Negative.

Multiplying or Divinding a Positive to a Positive the result will be a Positive.

iris [78.8K]3 years ago
4 0

Answer:

its -1.66666666667

Step-by-step explanation:

you are thinking of 5x-3, remember you have the number 5 dividedinto -3 parts

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Explain the mathematical motivation for expanding to the rational number set.
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Simplify the rational expression below
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8 0
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Dont Need Help Just Trying To Give Points 20+20=????
Elenna [48]
Thanks Lots! You're awesome
4 0
3 years ago
There is a beaker of 3.5% acid solution and a beaker of 6% acid solution in the science lab. Mr. Larson needs 200 milliliters of
oksian1 [2.3K]
Et x = the volume of the 3.5% solution 
<span>Let y = the volume 6% solution </span>

<span>(3.5%)x + (6%)y = (4.5%)(200) </span>
<span>0.035)x + 0.06y = 0.045(200) </span>
<span>0.035x + 0.06y = 9 ( Equation 1 )</span>

<span>x + y = 200 ( Equation 2 )</span>
<span>x = 200 - y </span>

<span>Substitute x = 200 - y into equation 1: </span>
<span>0.035x + 0.06y = 9 </span>
<span>0.035(200 - y) + 0.06y = 9 </span>
<span>7 - 0.035y + 0.06y = 9 </span>
<span>0.06y - 0.035y = 9 - 7 </span>
<span>0.025y = 2 </span>
<span>y = 2/(0.025) </span>
<span>y = 80 mL (the volume of 6% solution.)</span>

<span>Substitute y = 80 into equation 2: </span>
<span>x + y = 200 </span>
<span>x + 80 = 200 </span>
<span>x = 200 - 80 </span>
<span>x = 120 mL (the volume of the 3.5% solution.)</span>

<span>Therefore, Mr. Larson should combine 120 mL of the 3.5% solution </span>
<span>and 80 mL of the 6% solution to make 200 mL of 4.5% solution. </span>

<span>Answer is 120 mL of the 3.5% solution & 80 mL of the 6% solution

Hope I helped :)</span>
5 0
4 years ago
NEED THE ANSWER NOW 50 POINTS PLEASE HELP!
JulsSmile [24]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \dfrac{3 {x}^{2} y {}^{ - 1}}{27x  {}^{ - 3}  {y}^{8} }

Now, let's get the common terms out :

\qquad \sf  \dashrightarrow \:  \dfrac{3 {x}^{2} y {}^{ - 1}}{3 {x}^{2} {y}^{ - 1}(9 {x}^{ - 5} {y}^{9}    )}

cancel out the common terms in numerator and denominator

\qquad \sf  \dashrightarrow \:  \dfrac{1}{9 x  {}^{ - 5}  {y}^{9} }

\qquad \sf  \dashrightarrow \:  \dfrac{ {x}^{5} }{9   {}^{ }  {y}^{9} }

So, the correct choice is C

8 0
2 years ago
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