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4 years ago

Joe has a 28 foot long board. He needs to cut it into 24 equal length parts.How many feet should each section of the board be?

Mathematics

1 answer:

Ilya [14]4 years ago

6 0

28 divides by 24 is 1.1666667 which rounds to 1.17 <——answer

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Find X in the figure below.

Hitman42 [59]

<h3>Answer:</h3>

x = 3

<h3>Explanation:</h3>

The product of the lengths of segments from the intersection point to the circle is the same for both secants.

... 1×6 = 2×x

... 6/2 = x = 3 . . . . . divide by 2

_____

<em>Comment on secant geometry</em>

Interestingly, this relation is true whether the point of intersection of the secants is inside the circle or outside.

When it is outside, the product is of the distance to the near intersection with the circle and the distance to the far intersection with the circle.

6 0

3 years ago

J is the midpoint of hk. what is hj, jk, and hk

Lyrx [107]

Hj and jk are the same length line segments ( because the midpoint divides a line into two equal parts)
So hj = jk.

hk is the line segment which has the mid point j. It is the double of hj or jk. It can be the sum of hj and jk.
hj + jk = hk
or
2 * hj = hk
or
2 * jk = hk

4 0

3 years ago

Read 2 more answers

HELP, PLATO!!!!!!!

Keith_Richards [23]

Answer:

the law of cosines with ABC

7 0

2 years ago

3(x + y + h)=<br> Can someone help me with this

Nastasia [14]

Answer:

3x +3y +3h

that’s the farthest you can solve since you don’t know the variable’s values

4 0

3 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago