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kogti [31]
4 years ago
13

Joe has a 28 foot long board. He needs to cut it into 24 equal length parts.How many feet should each section of the board be?

Mathematics
1 answer:
Ilya [14]4 years ago
6 0
28 divides by 24 is 1.1666667 which rounds to 1.17 <——answer
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Jasmine goes bowling. She has $25.00 spend. She spends $4.50 to rent shoes. She spends $2.50 for each game she
NeTakaya

Answer:

25.00 < (with a line  under it) 4.50+2.50x

Step-by-step explanation:

3 0
3 years ago
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Solve the linear equation:<br><br> x-y=7<br><br> 0.5x+y=5
evablogger [386]

Add the equations.

x-y%2B0.5x%2By=7%2B5

1.5x=12

 

highlight%28x=8%29

Now use either equation to solve for y.

8-y=7

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4 0
3 years ago
Cot(90° − x) = 1 The value of x that satisfies this equation is Blank °.
Reil [10]

Answer:

x=90\degree

Step-by-step explanation:

The given trigonometric equation is

\cos(90\degree -x)=1

We take the inverse cosine of both sides to obtain;

(90\degree -x)=\cos^{-1}(1)

(90\degree -x)=0

Group similar terms t obtain;

-x=0-90\degree

x=90\degree

4 0
4 years ago
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Find the area of the shaded portion the one who answer first will get brainliest
slega [8]

Answer:

≈ 77 cm²

Step-by-step explanation:

The area of the shaded portion is calculated as

area of outer sector - area of inner sector

= (πR² - π r²) × \frac{60}{360} ( R is the outer radius, r is the inner radius )

= (π × 14² - π × 7² ) × \frac{1}{6}

= (196π - 49π ) ÷ 6

= 147π ÷ 6

≈ 77 cm² ( nearest whole number )

5 0
3 years ago
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HELPPPP<br> please help me answer this question-
erik [133]

Answer:

\displaystyle   GH  =  2 \sqrt{30}

\displaystyle FH = 2 \sqrt{10}

\displaystyle m \angle G =  {30}^{ \circ}

Step-by-step explanation:

<h3>QUESTION-2:</h3>

we are given a right angle triangle

it's a 30-60-90 triangle of which FH is the shortest side

remember that,in case of 30-60-90 triangle the the longest side is twice as much as the shortest side thus

our equation is

\displaystyle 2FH=4\sqrt{10}

divide both sides by 2

\displaystyle\frac{2FH}{2}= \frac{ 4 \sqrt{10} }{2}

\displaystyle FH =2 \sqrt{10}

<h3>Question-1:</h3>

in order to figure out GH we can use Trigonometry because the given triangle is a right angle triangle

as we want to figure out GH we'll use sin function

remember that,

\displaystyle  \sin( \theta)  =  \frac{opp}{hypo}

let our opp, hypo and \theta be GH, 4√10 and 60° respectively

thus substitute:

\displaystyle  \sin(  {60}^{ \circ} )  =  \frac{GH}{4 \sqrt{10} }

recall unit circle:

\displaystyle   \frac{ \sqrt{3} }{2}   =  \frac{GH}{4 \sqrt{10} }

cross multiplication:

\displaystyle   2 GH  =  4 \sqrt{10}  \times  \sqrt{3}

simplify multiplication:

\displaystyle   2 GH  =  4 \sqrt{30}

divide both sides by 2:

\displaystyle   GH  =  2 \sqrt{30}

<h3>QUESTION-3:</h3>

Recall that, the sum of the interior angles of a triangle is 180°

therefore,

\displaystyle m \angle G +  {60}^{ \circ}  + {90}^{ \circ}  =  {180}^{ \circ}

simplify addition:

\displaystyle m \angle G +  {150}^{ \circ}  =  {180}^{ \circ}

cancel 150° from both sides

\displaystyle m \angle G =  {30}^{ \circ}

6 0
3 years ago
Read 2 more answers
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