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3 years ago

How do you solve this problem.

Mathematics

2 answers:

Irina-Kira [14]3 years ago

6 0

Luke: 1 lap per day so a total of 4 laps
Alex: 3 laps per day so a total of 12 laps
Hope this will help you! :)

Harlamova29_29 [7]3 years ago

3 0

3=6 4=9 hope this helps

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Help me solve this.

almond37 [142]

Answer:

thx-step explanation:

6 0

3 years ago

an umbrella is made by stitching 10 triangular pieces of cloth of two different colours where each pieces measuring 48cm,48cm,an

mars1129 [50]

Answer:

Step-by-step explanation:

first we need to calculate the area of isosceles triangle having sides 48cm, 48cm and 30cm

a = 48

b= 30

Area of isosceles triangle using only sides = ½[√(a^2 − b^2 /4) × b]

= 1/2*30√( 48² - 1/4×30²)

=1/2*30√ (2304 -225)

=684sq cm

cost required to make umbrella= 10*684*5

= 34200

7 0

3 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago

Find the slope intercept form of the equation of the line that’s has the given properties (1 , 3) m=1/4

Helga [31]

Answer:

y = 1/4x + 11/4

Step-by-step explanation:

Given the slope, m = 1/4, and the point, (1, 3):

We can substitute these values into the slope-intercept form, y = mx + b, in order to solve for the y-intercept.

The y-coordinate (b) of the point, (0, b ) is the y-intercept of the line where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0.

y = mx + b

3 = 1/4(1) + b

3 = 1/4 + b

Subtract 1/4 from both sides:

3 - 1/4 = 1/4 - 1/4 + b

11/4 = b

The y-coordinate, b, of the y-intercept is 11/4.

Therefore, the slope-intercept form is: y = 1/4x + 11/4

Please mark my answers as the Brainliest if you find this explanation helpful :)

4 0

2 years ago

If you drive 130 miles and it takes you Two hours and six minutes and then you drive back on the same route but it takes you two

Vilka [71]

You can gain it by taking an hr and thirty min trip and on the way back takes hr and forty five min. That is how you gain your precious time back!!!✍️☃️⚽️

4 0

3 years ago