Three cards are drawn from an ordinary deck without replacement. Find the probability that all three are Hearts.
1 answer:
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Given: ∠ DEF
To construct: ∠TSZ ≅ ∠DEF
Construction: Consider the attachment
Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST
Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.
Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.
Step-04: Now, join the point SQ and extend up to Z such that EF = SZ
Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF
Answer:
P = 0.42
Step-by-step explanation:
This probability problem can be solved by building a Venn like diagram for each probability.
I say that we have two sets:
-Set A, that is the probability of receiving this virus through the email.
-Set B, that is the probability of receiving it through the webpage.
The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that = 0.17.
By email only
The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:
where A is the probability that the system receives the virus just through the email.
The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.
By webpage only
There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:
where B is the probability that the system receives the virus just through the webpage.
The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.
What is the probability that the virus does not enter the system at all?
So, we have the following probabilities.
- The virus does not enter the system: P
- The virus enters the system just by email: 23% = 0.23
- The virus enters the system just by webpage: 18% = 0.18
- The virus enters the system both by email and by the webpage: 17% = 0.17.
The sum of the probabilities is 100% = 1. So:
P + 0.23 + 0.18 + 0.17 = 1
P = 1 - 0.58
P = 0.42
There is a probability of 42% that the virus does not enter the system at all.