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3 years ago

Find the sum of 8a –2b + 3c and –3a +4b –3c

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

Answer: 5a + 2b

Step-by-step explanation:

Given

(8a - 2b + 3c) + (-3a + 4b - 3c)

Expand parentheses

=8a - 2b + 3c - 3a + 4b - 3c

Put like terms together

=(8a - 3a) + (4b - 2b) + (3c - 3c)

Combine like terms

=5a + 2b + 0

= $\boxed{5a+2b}$

Hope this helps!! :)

Please let me know if you have any questions

IRISSAK [1]3 years ago

4 0

ANSWER:
5a+2b

add the like terms together

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3 years ago

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2. n = 11

4. g = -2

6. t = 21

8. n = 4

10. y = -1

Step-by-step explanation:

2. 63 = -3(1 - 2n)

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4. -g + 2(3 + g) = -4(g + 1)

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$-g+2\times 3 + 2\times g = -4\times g + -4\times 1\\-g+6+ 2g=-4g-4\\\textrm{we will take all the g term the left side and the constant to the right side}\\4g-g+2g=-6-4\\5g=-10\\g=\frac{-10}{5}\\\therefore g=-2$

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Using distributive property A( B +C) = AB + AC we get

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8. -8 - n = -3(2n -4)

Using distributive property A( B +C) = AB + AC we get

$-8 - n = -3\times 2n - -3\times4\\-8-n=-6n+12\\\textrm{all the n terms to the left inside and the constant of the right-hand side}\\6n-n=8+12\\5n=20\\n=\frac{20}{5}\\ \therefore n= 4$

10. -4( 2 - y) + 3y = 3(y - 4)

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$-4\times 2 --4\times y + 3y = 3\times y -3\times 4\\-8+4y+3y =3y-12\\\textrm{all the y terms to the left side and the constant to the right side}\\4y+3y-3y=-12+8\\4y=-4\\y=\frac{-4}{4}\\ \therefore y=-1$

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3 years ago

Find the sum of 8a –2b + 3c and –3a +4b –3c​

Find the sum of 8a –2b + 3c and –3a +4b –3c