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3 years ago

Which ordered pair is a solution to the system of equations? x+y=3 2x+2y=6

1 answer:

6 0

X+y=3

x=3-y

2x+2y=6 using x from above...

2(3-y)+2y=6

6-2y+2y=6

6=6

This is always true, so there are an infinite number of solutions as they describe the same line.

*note however that (0,3) and (1.5, 1.5) are part of that infinite set of solutions

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Using the Quadratic Formula, which of the following is the solution to the quadratic equation x2 - 3x - 28 = 0?

algol13

The answer is (x+7)(x-4)

hence, the solution should be C

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3 years ago

Read 2 more answers

What is y-1 =2(x +3) in standard form?

miv72 [106K]

Answer:

y-1=2(x+3)

y-1=2x+6

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4 years ago

20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

<u>ANSWER: </u>

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago

The perimeter of a rectangular field is 320320 yd. the length is 2020 yd longer than the width. find the dimensions.

hichkok12 [17]

The sum of length and width is half the perimeter, 160 yd. The length is the average of the sum and difference of dimensions:
.. (160 +20)/2 = 90
Then the width is 160 -90 = 70

The rectangular field is 70 yd by 90 yd.

6 0

3 years ago

HELP I NEED TO PASS!!!!!

Brilliant_brown [7]

It’s b and d ? Both of those equations are the same if u haven’t noticed

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3 years ago