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torisob [31]
3 years ago
8

A researcher posts an online advertisement offering $25 in exchange for participation in a short study. The researcher accepts t

he first 10 people who respond to the advertisement. Which of the following statements is true about the sample? (1 point)
a
It is not a valid sample because it is only a short study.

b
It is a valid sample because money was offered to participants.

c
It is a valid sample because the first 10 people were selected to participate.

d
It is not a valid sample because it is not a random sample of the population.
Mathematics
2 answers:
valina [46]3 years ago
8 0

Answer:

A

Step-by-step explanation:

The study only consisted of 10 people. 10 people are not enough to come to a concrete conclusion for a project. Hope this helps!!

Lelu [443]3 years ago
8 0

Answer:

A) It is not a valid sample because it is only a short study.

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The probability solved by binomial distribution that all will survive is 0.8154.

<h3>What is Binomial distribution? </h3>

When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Computation of probability of all survived people from heart attack;

A heart attack patient has a 0.04 percent chance of dying from the attack (i.e., 4 of 100 die of the attack).

What is the likelihood that each of the five patients who experience a heart attack will survive?

We'll refer to a victory in this scenario as a heart attack (p = 0.04). In other words, we are interested in the likelihood that none of our n=5 patients will die (0 successes).

Each attack has a chance of being fatal or not, with a probability of 4 percent for all patients, and each patient's result is independent.

Assume for the purposes of this example that the five individuals being examined are unrelated, of the same age, and free of any concomitant disorders.

By binomial distribution,

\begin{gathered}P(0 \text { successes })=\frac{5 !}{0 !(5-0) !} 0.04^{0}(1-0.04)^{5-0} \\P(0 \text { successes })=\frac{5 !}{5 !}(1)(0.96)^{5}=(1)(1)(0.8154)=0.8154\end{gathered}

Therefore, with a 4 % chance that anyone will die, there is an 81.54% chance that every patient will survive the onslaught. The outcomes in this example could be 0, 1, 2, 3, 4 or 5 successes (fatalities).

To know more about Binomial Distribution, here

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Answer:

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Step-by-step explanation:

Given

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= \frac{16}{9}p² - 8pq - 8pq + 36q² ← collect like terms

= \frac{16}{9}p² - 16pq + 36q²

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