1. What is the extraneous solution of √x−3 + x = 9?

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

3 0

Answer:

1. x = 12

2. 3∛4 feet.

Step-by-step explanation:

1. We are given the equation of x as $\sqrt{x - 3} + x = 9$ and we have to find the extraneous solution of the equation.

Now, $\sqrt{x - 3} + x = 9$ ............. (1)

⇒ $\sqrt{x - 3} = 9 - x$

Squaring both sides we get,

⇒ x - 3 = 81 - 18x + x²

⇒ x² - 19x + 84 = 0

⇒ x² - 12x - 7x + 84 = 0

⇒ (x - 12)(x - 7) = 0

⇒ x = 12 or 7.

Now, putting x = 12 in the equation (1) we get,

$\sqrt{12 - 3} + 12 \neq 9$

Again, putting x = 7 in the equation (1) we get,

$\sqrt{7 - 3} + 7 = 9$

Therefore, x = 12 is an extraneous solution of this equation. (Answer)

2. The volume of a cube with side lengths a ft. is given to be 108 ft³.

So, a³ = 108

⇒ a = 3∛4 feet.

Therefore, the length of the sides of the cube are each 3∛4 feet. (Answer)

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