All categories

3 years ago

What are the weights (in Newton’s) for the given masses 22.1,33.5,41.3,59.2,78

Mathematics

1 answer:

Blababa [14]3 years ago

4 0

Answer:

1. 216.8 N

2.328.635 N

3. 405.153 N

4. 580.752 N

5. 765.18 N

Step-by-step explanation:

1. Let the mass is 22.1 kg, then the weight in Newton will be (22.1 × 9.81) = 216.8 N {Where acceleration due to gravity is 9.81 m/sec²}

2. Let the mass is 33.5 kg, then the weight in Newton will be (33.5 × 9.81) = 328.635 N {Where acceleration due to gravity is 9.81 m/sec²}

3. Let the mass is 41.3 kg, then the weight in Newton will be (41.3 × 9.81) = 405.153 N {Where acceleration due to gravity is 9.81 m/sec²}

4. Let the mass is 59.2 kg, then the weight in Newton will be (59.2 × 9.81) = 580.752 N {Where acceleration due to gravity is 9.81 m/sec²}

5. Let the mass is 78 kg, then the weight in Newton will be (78 × 9.81) = 765.18 N {Where acceleration due to gravity is 9.81 m/sec²}

(Answer)

You might be interested in

Is the equation of ellipse a function?

denpristay [2]

The equation of ellipse is x²/a² + y²/b² = 1, it can be written as
y =sqrt (b² - (b²/a²) x²), so it is a function

7 0

4 years ago

At an automobile factory, 1849 parts are made in 4 hours. What is the average rate at which parts are made per hour?

Rudiy27

Just divide "1849 parts" by "4 hours:" the average rate is 1849/4 parts/hour,

or 1849 parts/ 4 hours, or 462.25 parts/hour, or (rounded off) 462 parts/hour.

8 0

4 years ago

Read 2 more answers

10. What is the circumference of a circle with a diameter of 12 in?

OlgaM077 [116]

C≈37.7in

Hope this helped

also could you make me brainliest ty

6 0

4 years ago

Read 2 more answers

Let f (x)=1/x and g (x)=x^2+5x. A. Find (f×g)(x). B. Find the domain and range of (f×g)(x).

Ira Lisetskai [31]

we are given

$f(x)=\frac{1}{x}$

$g(x)=x^2+5x$

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

$(fXg)(x)=\frac{1}{x} (x^2+5x)$

we can simplify it

$(fXg)(x)=\frac{1}{x} (x(x+5))$

$(fXg)(x)=x+5$

(B)

Domain:

Firstly, we will find domain of f(x) , g(x) and (fxg)(x)

and then we can find common domain

Domain of f(x):

$f(x)=\frac{1}{x}$

we know that f(x) is undefined at x=0

so, domain will be

$(-\infty,0)$ ∪ $(0,\infty)$

Domain of g(x):

$g(x)=x^2+5x$

Since, it is polynomial

so, it is defined for all real values of x

now, we can find common domain

so, domain will be

$(-\infty,0)$ ∪ $(0,\infty)$ ..............Answer

Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

Range of f(x):

$f(x)=\frac{1}{x}$

we know that range is all possible values of y for which x is defined

since, horizontal asymptote will be at y=0

so, range is

$(-\infty,0)$ ∪ $(0,\infty)$

Range of g(x):

$g(x)=x^2+5x$

Since, it is quadratic equation

so, its range will be

$[-6.25,\infty)$

now, we can find common range

so, range will be

$(-6.25,0)$ ∪ $(0,\infty)$ .............Answer

6 0

3 years ago

What is the slope of the line segment? a 1/4 b -1/4 c 4 d 4

galina1969 [7]

to get the slope of any line, we can simply use two points off of it, for this one, say (3,12) and (4,16)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{12})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{16}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{16-12}{4-3}\implies \cfrac{4}{1}\implies 4$

7 0

3 years ago