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Pavel [41]
3 years ago
11

The mass of Saturn is approximately 6 × 10^26 kg, while the mass of Mercury is approximately 3 × 10^23 kg. Which of the followin

g is true?
A. The mass of Mercury is approximately two hundred times the mass of Saturn.

B. The mass of Mercury is approximately two thousand times the mass of Saturn.

C. The mass of Saturn is approximately two thousand times the mass of Mercury.

D. The mass of Saturn is approximately two hundred times the mass of Mercury.

(I added a few extra points to it, to help out)
Mathematics
1 answer:
yanalaym [24]3 years ago
5 0

The right answer is:

C. The mass of Saturn is approximately two thousand times the mass of Mercury.

Step-by-step explanation:

We will find the ratio of both masses to compare them.

Given

Mass of Saturn = S = 6*10^{26}\ kg

Mass of Mercury = M = 3 * 10^{23}\ kg

The ratio of larger mass to smaller is:

\frac{S}{M} = \frac{6*10^{26}}{3*10^{23}}\\= \frac{6*1000*10^{23}}{3*10^{23}}\\= 2*1000\\=2000\ times

Hence,

The right answer is:

C. The mass of Saturn is approximately two thousand times the mass of Mercury.

Keywords: Mass, Ratio

Learn more about mass at:

  • brainly.com/question/1369568
  • brainly.com/question/1357167

#LearnwithBrainly

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Solve please, Thanks.
nataly862011 [7]

Answer:

i dont get it

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the center and radius of the following circle (x - 5) ^ 2 + (y + 2) ^ 2 = 16
murzikaleks [220]

Answer:

Step-by-step explanation:

if center=(h,k)

radius=r

eq. of circle is (x-h)^2+(y-k)^2=r^2

given eq. is (x-5)^2+(y+2)^2=16=4^2

comparing

center =(5,-2)

radius r=4

4 0
3 years ago
Hope an expert can help with this
Citrus2011 [14]

For Range you take the biggest number and subtract it with the smallest. So:

January = E14,000

Febuary = E9,000

March = E10,000

All Three Months = E17,000

Hope this helps,pleeease vote as brainliest!

5 0
3 years ago
Which of the following is the equation of the function below?
puteri [66]

Answer:

The equation of the graph below is y = 0.5 csc[0.5(x + π/2)] - 1 ⇒ 3rd answer

Step-by-step explanation:

* Lets revise the trigonometry transformation

- If the equation is y = A csc(B(x + C)) + D

# Amplitude is A

- The Amplitude is the height from the center line to the peak .

  Or we can measure the height from highest to lowest points and

  divide that by 2

# period is 2π/B

- The Period goes from one peak to the next

# phase shift is C (positive is to the left)

- The Phase Shift is how far the function is shifted horizontally

  from the usual position.

# vertical shift is D

- The Vertical Shift is how far the function is shifted vertically from

 the usual position.

- If y = csc(x)

∴ A = 1 , B = 1 , C = 0 , D = 0

- That means the amplitude is 1, the period is 2π, no phase shift

 or vertical shift

* Now lets solve the problem

- From the graph

# The amplitude = (-0.5 - -1.5)/2 = 0.5

∴ A = 0.5

# The period is from 2.5π to -1.5π

∴ The period is 4π

∵ The period = 2π/B

∴ 4π = 2π/B ⇒ by cross multiplication

∴ B = 2π/4π = 1/2 = 0.5

* There is only one answer has A = 0.5 and B = 0.5

∴ y = 0.5 csc[0.5(x + π/2)] - 1

* The equation of the graph below is 0.5 csc[0.5(x + π/2)] - 1

* For more understand look to the color graph

- The blue graph is y = csc(x)

- The green graph is y = 0.5 csc[0.5(x + π/2)] - 1

5 0
3 years ago
Read 2 more answers
Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

3 0
2 years ago
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