A event would be five I think and the event of b would be nine
The expected value of the discrete distribution, if you have to pay $.50 to pick one package at random, is of -$0.08.
<h3>What is the mean of a discrete distribution?</h3>
The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.
For this problem, considering the cost of $0.5, the distribution is given as follows:
- P(X = 0.2) = 12/(12 + 15 + 23) = 12/50 = 0.24.
- P(X = -0.1) = 15/(12 + 15 + 23) = 15/50 = 0.3.
- P(X = -0.2) = 23/(12 + 15 + 23) = 23/50 = 0.46.
Hence the expected value is given by:
E(X) = 0.2 x 0.24 - 0.3 x 0.1 - 0.2 x 0.46 = -$0.08.
More can be learned about the expected value of a discrete distribution at brainly.com/question/13008984
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Since as of now we're saying that the probability of having a girl is 1/2, we can say:
1/2 * 1/2 * 1/2 * 1/2, because then you're saying a one half chance of having a girl times another one half chance of having a girl, etc.
That ends up to be 1/16.
Answer:
<u>Geometry</u>
AC equals 13x + 7
<u>Algebra</u>
1. x = -16
2. x = 2
3. 2x^2 - 5x -7
4. (2x + 1)(x - 5)
Step-by-step explanation:
