The number is already in prime factored form. The prime factors are 2, 3, 5, and 7. If we multiply everything out then we end up with 2100
Answer:
2:3
Step-by-step explanation:
A total of 30 students with 12 girls so its 12/30 & its the balance of 18 boys or 18/30
12:18 ÷ by 2 on both sides is.6:9 & 2:3, Answer is Ratio of 2:3.
Answer:
114°
Step-by-step explanation:
The exterior angle is the sum of the remote interior angles.
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<h3>setup</h3>
(11x +15)° = 60° +6x°
<h3>solution</h3>
5x = 45 . . . . . . . . . divide by °, subtract 15+6x
x = 9 . . . . . . . . . . divide by 5
The measure of exterior angle KMN is ...
m∠KMN = (11(9) +15)° = 114°
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<em>Additional comment</em>
Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...
60° +6x° +M = 180°
(11x +15)° +M = 180°
Equating these expressions for 180° and subtracting M gives the relation we used above:
(11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°
(11x +15)° = 60° +6x° . . . . . . . . . . . subtract M
This is also described by "supplements to the same angle are equal."
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
