Answer:
$425.6 should be budgeted for weekly repairs and maintenance.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean $400 and standard deviation $20.
This means that 
How much should be budgeted for weekly repairs and maintenance to provide that the probability the budgeted amount will be exceeded in a given week is only 0.1?
This is the 100 - 10 = 90th percentile, which is X when Z has a p-value of 0.9, so X when Z = 1.28.




$425.6 should be budgeted for weekly repairs and maintenance.
Answer:
Number of sundaes = 36
Number of banana split = 28
Step-by-step explanation:
On that day, let the number of sundaes sold be x
Now, since they sold 8 more sundaes than banana, the number of bananas sold is x-8
So the cost of sundaes sold will be 2 * x = 2x
the total cost of banana splits sold will be 3(x-8) = 3x -24
The addition of both equals 156
Hence;
2x + 3x-24 = 156
5x -24 = 156
5x = 156 + 24
5x = 180
x = 180/5
x = 36
So
number of sundaes sold is 36 while the number of bananas split sold is 36-8 = 28
Unit price so compare
2 gets 64 or 7.50 get 256
grocery store 2:64=1:32=32 oz per $1
wholesale club 7.5:256=1:34.133=34.133 oz per $1
wholesale club gets you more oz of juice for the same price
A: 32 oz per $1 or $0.031 per 1 oz
B: 34.133 oz per $1 or $0.029 per 1 oz
C: best deal is at wholesale club