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Kazeer [188]
3 years ago
9

Perform the indicated operation. y^2+3y-10/3y+15

Mathematics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

Step-by-step explanation:

Hello, please consider the following.

We take y different from -5, as dividing by 0 is not allowed and we can compute as below.

\dfrac{y^2+3y-10}{3y+15}=\dfrac{(y+5)(y-2)}{3y+15}\\\\=\dfrac{(y+5)(y-2)}{3(y+5)}\\\\\large \boxed{\sf \bf \ \ =\dfrac{y-2}{3} \ \ }

Thank you

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