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fgiga [73]
3 years ago
5

A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac

tive after 40 minutes? Round the answer to the nearest tenth of a gram, and do not include the unit in your answer.
Mathematics
1 answer:
sammy [17]3 years ago
5 0

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant =  0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g

     

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

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I will mark either the best or the first answer.<br> Btw, please don't answer with nonsense.
boyakko [2]

Answer:

6.8, 26.2, -7.8, -10.2, 2.6, -12.9

Step-by-step explanation:

20. is 6.78232 Rounded answer is 6.8

21. 26.172504657 rounded to the nearest tenth is 26.2

22. is -7.8102496759 rounded to the nearest tenth is -7.8

23. -10.246950766 rounded to the nearest tenth is -10.2

24. is 2.5980762114 rounded to the nearest tenth is 2.6

25. -12.942179106 rounded to nearest tenth is -12.9

7 0
3 years ago
Read 2 more answers
Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.
Sonja [21]
<h3>Answer:  Rhombus</h3>

======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\

Segment AB is exactly \sqrt{17} units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2)  = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\

Segment AB has a slope of 1/4.

Do the same for BC

B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2)  = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

4 0
2 years ago
Read 2 more answers
Dkendbdjdbebdbdbdjdnd
sertanlavr [38]

Answer:

5/2

Step-by-step explanation:

The 5^-3 and 5^6 cancel out to be 5^3. Then the 5^3 cancels out with the 5^2 in the denominator and leaves you with just a 5. The 2^2 makes the 2^3 in the denominator just 2. So, you are left with 5/2! Hope this helps.

7 0
3 years ago
A. 55<br> b. 70<br> c. 110<br> d. 125
morpeh [17]

Answer:

b

Step-by-step explanation:

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vova2212 [387]
3(10) + 5y = 20
5y = 20 - 30
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