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Afina-wow [57]
3 years ago
6

C^1/2+c^1/3 for c=64

Mathematics
1 answer:
prisoha [69]3 years ago
7 0

Answer:

12

Step-by-step explanation:

\huge {c}^{ \frac{1}{2} }  +  {c}^{ \frac{1}{3} }  \\  \\ \huge =  {64}^{ \frac{1}{2} }  +  {64}^{ \frac{1}{3} } \\(plug \: c = 64)   \\  \\ \huge =  { ({8}^{2}) }^{ \frac{1}{2} }  +  {( {4}^{3} )}^{ \frac{1}{3} }   \\  \\  \huge =  {8}^{2 \times  \frac{1}{2} }  +  {4}^{3 \times  \frac{1}{3} }  \\  \\ \huge = 8 + 4 \\ \\ \huge = 12

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