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NeX [460]
3 years ago
9

How do the components of a vector transform under a translation of coordinates?

Physics
1 answer:
Rus_ich [418]3 years ago
8 0
Vectors are invariant under translation. This means that they are unaffected or unchanged even if the coordinates are translated. So while the coordinates of two points are changed or moved during translation, the distance between the two points does not change. The best way to picture this out is using real life scenario. For example, you and I are at rest relative to each other but sitting on a plane at different locations, then we will have a fixed distance. Now the plane flies and its overall location is changed, similarly our individual coordinates also change but the distance between us will remain the same.<span>

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Explain mantle convection.
inysia [295]

Answer:

Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.

Explanation:

7 0
2 years ago
You are designing a system for moving aluminum cylinders from the ground to a loading dock. You use a sturdy wooden ramp that is
djyliett [7]
We are given with
l = 8.00 m
θ = 37.0°
m = 470 kg
r = 0.300 m
μ = 0.120

To solve the magnitude of the force required to roll the cylinders up the ramp, we do a force balance
F = Ff
F = μFn
F = mgμ sin θ
substituting the given values
F = 470 (9.81) (0.120) sin 37.0°
F = 333.97 N<span />
6 0
3 years ago
Read 2 more answers
During development, the cells in these organisms become specialized.
Y_Kistochka [10]

Answer:

A- multicellular

Explanation:

fertilized egg I think that is the answer

7 0
3 years ago
What kind of engine do most cars use today
Nadusha1986 [10]

Answer:

4 stroke 4 cylinder Natural Aspirated Gasoline engine

Explanation:

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4 0
3 years ago
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A hydraulic jack has a small piston area A1 = 2 m^2 and the large piston area A2 = 20 m^2. A 1500 Kg car needs to be lifted. a)
Alex777 [14]

Answer:

1471.5 Newton

10

Explanation:

Small piston area = A₁ = 2 m²

Large piston area A₂ = 20 m

m = Mass of car = 1500 kg

g = Acceleration due to gravity = 9.81 m/s²

Force

F = mg = 1500×9.81 = 14715 N

Force applied by car is 14715 N

a) Pascal's law

\frac{F_1}{A_1}=\frac{F_2}{A_2}\\\Rightarrow F_1=F_2\frac{A_1}{A_2}\\\Rightarrow F_1=14715\frac{2}{20}=1471.5

Force required is 1471.5 Newton

b) Mechanical advantage

\frac{F_2}{F_1}=\frac{14715}{1471.5}=10

Mechanical advantage is 10

5 0
3 years ago
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