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LiRa [457]
2 years ago
10

A weight lifter is trying to lift a 1500-N weight but can apply a force of only 1200 N on the weight. One of his friends helps h

im lift it all the way. What force was applied to the weight by the weight lifter's friend?
Physics
1 answer:
aliya0001 [1]2 years ago
4 0

Answer:

300 N

Explanation:

We have three forces acting on the object:

- W = 1500 N, downward: the weight of the object

- F1 = 1200 N, upward: the force exerted by the first man

- F2, upward: the force exerted by the friend

In order to lift the object, the sum of the two forces F1 and F2 must be at least equal to the weight of the object W. Therefore we can write

F_1 +F_2 = W

And from this equation, we can find the magnitude of F2:

F_2 = W-F_1 = 1500 N-1200 N=300 N

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Explanation:

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A wave passes along the surface of the water in a ripple tank. Describe the motion of a molecule on the surface as the water pas
laila [671]

Answer:

Explanation:

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As the wave propagates from one point to another on the surface of water transferring energy, a molecule of water on its surface vibrates upwards and downwards. Its motion is perpendicular to the direction of propagation of the wave. After the vibration, it comes back to its initial position.

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3 years ago
Two sealed 1 l containers full of gas are at room temperature. Container a has a pressure of 4 atm and container b has a pressur
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Answer:

The number density of the gas in container A is twice the number density of the gas in container B.

Explanation:

Here we have

P·V =n·R·T

n = P·V/(RT)

Therefore since V₁ = V₂ and T₁ = T₂

n₁ = P₁V₁/(RT₁)

n₂ = P₂V₂/(RT₂)

P₁ = 4 atm

P₂ = 2 atm

n₁ = 4V₁/(RT₁)

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∴ n₁ = 2 × n₂

Therefore, the number of moles in container A is two times that in container B and the number density of the gas in container A is two times the number density in container B.

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