2 1/2 for $6.25 is the answer
Answer:
The length of the call that would cost the same with both cards is 5 minutes.
Step-by-step explanation:
Hi there!
The cost with card A can be expressed as follows:
cost A = 30 + 2 · m
Where "m" is the length of the call in minutes.
In the same way, the cost of card B will be:
cost B = 10 + 6 · m
Where "m" is the length of the call in minutes.
We have to find the value of "m" for which the call would cost the same with both cards.
Then:
cost A = cost B
30 + 2 · m = 10 + 6 · m
Subtract 10 and 2 · m to both sides of the equation:
30 - 10 = 6 · m - 2 · m
20 = 4 · m
Divide by 4 both sides of the equation:
20/4 = m
5 = m
The length of the call that would cost the same with both cards is 5 minutes.
Have a nice day!
Answer:
161.34
Step-by-step explanation:
Answer:
Let x be the number of gallons of the 20% solution and let y be the number of gallons of the 5% solution.
Your system would be:
x+y=15
0.2x+0.05y=(0.13)(15)
Solve the system using either elimination or substitution method, or a combination of the two.
I am available for one-on-one help. Don't be afraid to ask!
The measure of the angle created by the car's turning is 105°
Step-by-step explanation:
Given : a car is traveling east on 4th Street and turns onto King Avenue heading northeast.
We have to calculate the measure of the angle created by the car's turning.
Since, car is travelling in east direction on 4th street that is from A to D as shown below in image by arrow.
Then at point B, the car turns toward King Avenue heading northeast. that is B to C as shown below in image
Since, we need to calculate the measure of the angle created by the car's turning that is measure of ∠ABC.
AD is a straight line, thus measure of any angle at line segment AD is 180° as angles on one side of a straight line always add to 180 degrees
Therefore, at B,
∠ABC + ∠CBD = 180°
Aldo given , ∠CBD = 75°
Thus, the measure of ∠ABC is ,
⇒ ∠ABC = 180° -∠CBD
⇒ ∠ABC = 180° - 75°
⇒ ∠ABC = 105°
Thus, the measure of the angle created by the car's turning is 105°
