Answer:
a) Figure attached
b) ![P(X](https://tex.z-dn.net/?f=%20P%28X%3C130%20min%29%3D%20F%28130%29%20%3D%20%5Cfrac%7B130-120%7D%7B20%7D%3D0.5)
c) ![P(X>135) =1-P(X](https://tex.z-dn.net/?f=%20P%28X%3E135%29%20%3D1-P%28X%3C135%29%20%3D%201-%20F%28135%29%20%3D%201-%20%5Cfrac%7B135-120%7D%7B20%7D%3D%200.25)
d) ![E(X) =\frac{a+b}{2}= \frac{120+140}{2}= 130min](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%5Cfrac%7Ba%2Bb%7D%7B2%7D%3D%20%5Cfrac%7B120%2B140%7D%7B2%7D%3D%20130min)
Step-by-step explanation:
2 hr = 120 min
2hr 20 min = 120+20 = 140 min
Let X the random variable that represent "flight time". And we know that the distribution of X is given by:
For this case the density function for A is given by:
![f(X) = \frac{1}{b-a}= \frac{1}{20} , 120\leq X \leq 140](https://tex.z-dn.net/?f=%20f%28X%29%20%3D%20%5Cfrac%7B1%7D%7Bb-a%7D%3D%20%5Cfrac%7B1%7D%7B20%7D%20%2C%20120%5Cleq%20X%20%5Cleq%20140%20)
And
for other case
Part a
For this case we can see the figure attached. We see that the probability density function is defined between 120 and 140 minutes.
Part b
The arrival time is 2hr 5 min = 125 min. So then 5 minutes leate means 130 min
For this case we want to find this probability:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C130%20min%29)
And we can use the cumulative distribution function for X given by:
![F(X) = \frac{x-120}{140-120} = \frac{x-120}{20} , 120\leq X \leq 140](https://tex.z-dn.net/?f=%20F%28X%29%20%3D%20%5Cfrac%7Bx-120%7D%7B140-120%7D%20%3D%20%5Cfrac%7Bx-120%7D%7B20%7D%20%2C%20120%5Cleq%20X%20%5Cleq%20140%20)
And if we use this formula we got:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C130%20min%29%3D%20F%28130%29%20%3D%20%5Cfrac%7B130-120%7D%7B20%7D%3D0.5)
Part c
For this case more than 10 minutes late means 125 +10 = 135 min or more, so we want this probability:
![P(X>135)](https://tex.z-dn.net/?f=%20P%28X%3E135%29)
And using the complement rule we have:
![P(X>135) =1-P(X](https://tex.z-dn.net/?f=%20P%28X%3E135%29%20%3D1-P%28X%3C135%29%20%3D%201-%20F%28135%29%20%3D%201-%20%5Cfrac%7B135-120%7D%7B20%7D%3D%200.25)
Part d
The expected value for the uniform distribution is given by:
![E(X) =\frac{a+b}{2}= \frac{120+140}{2}= 130min](https://tex.z-dn.net/?f=%20E%28X%29%20%3D%5Cfrac%7Ba%2Bb%7D%7B2%7D%3D%20%5Cfrac%7B120%2B140%7D%7B2%7D%3D%20130min)
I'm not going to give you the answer... sorry. But what you need to do is divide the colors into as much as you can and try to make as many bracelets as you can with the same number of beads. Does that make sense?
Answer:
A. The amount per text message.
B. 16x x y = 3.20
Step-by-step explanation:
A. the amount per text message doesn't change, only the amount of times you message does.
B. (below)
X- The amount of messages sent.
Y- The amount of months.
<span>Answer: the last option: 10%
Explanation:
1) Plan B: Treatment with Drug Y—if not effective, treatment with Drug X
2) The two drugs work independent of each other => joint probability equals the product of the individual probabilities.
3) probability of drug y is not effective = 1 - probability of being effective = 1 - 0.6 = 0.4
4) probability of drug x is not effective = 1 - probability of being effective = 1 - 0.75 = 0.25
5) Joint probability of being not effective = 0.4 × 0.25 = 0.10
6) 0.10 = 10%
Therefore the answer is 10%
</span>
Answer:
The percent increase is 100%
Step-by-step explanation:
The original cost of the video games is $25. They sell them for $50.