Consider the given vector equation. r(t) = 2eti + 3e−tj (a) find r'(t). r'(t) = <2et,−3e−t> (b) sketch the plane curve tog
ether with the position vector r(t) and the tangent vector r'(t) for the given value of t = 0.
1 answer:
(a) Differentiate each of the components to get r'(t). The rule is
.. d/dt (a*e^(bt)) = a*b*e^(bt)
The answer you have shown is the correct one.
(b) See the figure. The red curve is the position r(t) for 0 ≤ t ≤ 2. The dashed orange line is the tangent line, whose equation is
.. L(t) = r(0) +r'(0)*t = (2 +2t)i +(3 -3t)j
.. d/dt (a*e^(bt)) = a*b*e^(bt)
The answer you have shown is the correct one.
(b) See the figure. The red curve is the position r(t) for 0 ≤ t ≤ 2. The dashed orange line is the tangent line, whose equation is
.. L(t) = r(0) +r'(0)*t = (2 +2t)i +(3 -3t)j
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Answer: the height of the lighthouse is 838.8 feet
Step-by-step explanation:
The right angle triangle ABC illustrating the scenario is shown in the attached photo.
The angle of depression and angle A are alternate angles, hence, they are the equal.
The height, h of the lighthouse represents the opposite side of the right angle triangle. The distance of the boat from the foot of the lighthouse represents the adjacent side of the right angle triangle.
To determine h, we would apply
the tangent trigonometric ratio.
Tan θ, = opposite side/adjacent side. Therefore,
Tan 62 = h/446
h = 446tan62 = 446 × 1.8807
h = 838.8 feet to the nearest tenth.
