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Morgarella [4.7K]
3 years ago
10

Consider the given vector equation. r(t) = 2eti + 3e−tj (a) find r'(t). r'(t) = <2et,−3e−t> (b) sketch the plane curve tog

ether with the position vector r(t) and the tangent vector r'(t) for the given value of t = 0.

Mathematics
1 answer:
Fofino [41]3 years ago
6 0
(a) Differentiate each of the components to get r'(t). The rule is
.. d/dt (a*e^(bt)) = a*b*e^(bt)
The answer you have shown is the correct one.

(b) See the figure. The red curve is the position r(t) for 0 ≤ t ≤ 2. The dashed orange line is the tangent line, whose equation is
.. L(t) = r(0) +r'(0)*t = (2 +2t)i +(3 -3t)j

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