answer:
in order to construct 75°, you need to use a protractor and a compass
step-by-step explanation:
here is a step-by-step explanation from an online source
- step 1: draw a line segment with endpoint O and A
- step 2: draw an arc with O as centre cutting the line segment OA at point B with a compass
- step 3: keeping the radius same, draw an arc with B as centre cutting the arc at C
- step 4: keeping the radius same, and C as the center, draw an arc intersecting the arc drawn in the previous step at D
- step 5: with any radius, draw two arcs with C and D as a center. intersect these two arcs at E
- step 6: join OE. angle EOA is the angle with measurement of 90 degrees
- step 7: now the line OE intersect the arc at the point F
- step 8: taking F and C as a center, make an arc with a radius of more than half of the measurement FC. the arc intersects at point H
- step 9: join the point H and O. angle HOA is the angle obtained of measurement 75 degrees
- step 10: angle HOA is the desired angle
The solution is
We group like terms, to obtain;
Simplify to get,
We further simplify to get;
This can also be rewritten as;
Or
![(-\infty 3] \cup (18,+ \infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%203%5D%20%5Ccup%20%2818%2C%2B%20%5Cinfty%29)
This can be represented on the number line as shown in the diagram.
Answer: It will arrive at 5:55 P.M
Step-by-step explanation:
The answer is B.
I tried putting 9 for a and 7 for B. cos(9-7)+cos(9+7) = 2cos(9)cos(7)
Answer:
3125*k^9 + y^3 is an integer my closure property.
but 5^(1/3) is not an integer, which forces z to be irrational.
Note that there is no way an integer value can rationalize 5^(1/3)
Step-by-step explanation:
x^3 = 25z^3 - 5y^3
x^3 = 5 ( 5z^3 - y^3)
x = (5 ( 5z^3 - y^3) )^(1/3) must be an integer
= 5^(1/3) * (5z^3 - y^3)^(1/3)
Then (5z^3 - y^3)^(1/3) = 25*k^3 for some integer k
5z^3 - y^3 = 15625*k^9
5z^3 = 15625*k^9 + y^3
z^3 = 3125*k^9 + (1/5)*y^3
z = ( 3125*k^9 + (1/5)*y^3 )^ ( 1/3)
