Answer:
6. 5 % is the answer
Step-by-step explanation:
formula =
<em>R</em><em> </em><em>=</em><em> </em><em>I</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em>0</em><em> </em><em>/</em><em> </em><em>P</em><em> </em><em>×</em><em> </em><em>T</em>
Answer:
x
=
y
=
A
E
=
2
x
=
E
C
=
y
+
4
=
D
E
=
x
=
E
B
=
2
y
−
1
A
C
=
B
D
=
E
=
Step-by-step explanation:
The correct answer is b. 14(m-8).
This is because it says that the weight of the boxes drew lifted were 8 pounds less than what marco lifted. This can be represented by m-8. You then need to multiply this by the amount of boxes that drew lifted, or 14.
In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.
In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.
Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
Answer:
sometimes similar to a scelene triangle because we can never
