Answer:
yes
Step-by-step explanation:
mark brainliest
Answer:
Step-by-step explanation:
Let the number of cars be x and buses be y
<u>Then we have below inequalities as per given:</u>
- 5x + 32y ≤ 1310
- x + y ≤ 135
It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income
<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>
<u>Substitute it in the first one:</u>
- 5(135 - y) + 32y ≤ 1310
- 675 - 5y + 32y ≤ 1310
- 27y ≤ 1310 - 675
- 27y ≤ 635
- y ≤ 635/27
- y≤ 23.5
The greatest number of buses is 23
Option D. 23 is correct
I hope this helps you
y=-2x
x+3.(-2x)=15
x-6x=15
-5x=15
x=-3
y=-2.-3=6
Formula: A = pq/2
p = d1
q = d2
Substitute with the given values and solve.
A = 12*14/2
A = 168/2
A = 84
Therefore, the ansewr is 84in²
Best of Luck!
Just divide 8 by 2 and you'll get 4
Each container is 2 ounces so do 75 times 4 and you'll get 300 calories