Answer:
The values of 'x' are -1.2, 0, 0, or
.
Step-by-step explanation:
Given:
The equation to solve is given as:
Factoring from all the terms, we get:
Now, rearranging the terms, we get:
Now, factoring from the first two terms and 6 from the last two terms, we get:
Now, equating each factor to 0 and solving for 'x', we get:
There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.
Therefore, the values of 'x' are -1.2, 0, 0, or
.
Answer:
So, the correct option is A. x = 9, y = 14 , Sides are 11 and 20
Step-by-step explanation:
P.S - the exact question is -
As given in the question ,
Side AB = Side AD
⇒y - 3 = x + 2
⇒y - x = 2 + 3 = 5
⇒y - x = 5 .........(1)
Also, given
Side BC = Side CD
⇒2x + 2 = x + 11
⇒2x - x = 11 - 2
⇒x = 9
∴ equation (1) becomes
y - 9 = 5
⇒y = 5 + 9 = 14
⇒y = 14
∴ we get
x = 9, y = 14
Now,
as given ,
Side AB = y - 3
⇒ AB = 14 - 3 = 11
Side BC = 2x + 2
⇒ BC = 2(9) + 2 = 18 + 2 = 20
Side CD = x + 11
⇒ CD = 9 + 11 = 20
Side DA = x + 2
⇒DA = 9 + 2 = 11
∴ we get
The sides are 11 and 20
So,
The correct option is A. x = 9, y = 14 , Sides are 11 and 20
